Determine the missing step for solving the quadratic equation by completing the square.



0 = –6x2 + 24x – 5


5 = –6x2 + 24x


5 = –6(x2 – 4x)


inside the parentheses and .


–19 = –6(x – 2)2


StartFraction 19 Over 6 EndFraction = (x – 2)2


Plus or minus StartRoot StartFraction 19 Over 6 EndFraction EndRoot = x – 2


The two solutions are Plus or minus StartRoot StartFraction 19 Over 6 EndFraction EndRoot.

Respuesta :

Answer:

Missing step is "Add and subtract 4 in the parenthesis." The resulted equation is [tex]5=-6(x-2)^2+24[/tex].

Step-by-step explanation:

The given equation is

[tex]0=-6x^2+24x-5[/tex]

Step 1: Add 5 on both sides.

[tex]5=-6x^2+24x[/tex]

Step 2: Taking out 6 as common factor.

[tex]5=-6(x^2-4x)[/tex]

If an expression is defined as [tex]x^2+bx[/tex], then add [tex](\frac{b}{2})^2[/tex] in the expression to make it perfect square.

Here b=-4,

[tex](\frac{b}{2})^2=(\frac{-4}{2})^2=4[/tex]

Step 3: Add and subtract 4 in the parenthesis.

[tex]5=-6(x^2-4x+4-4)[/tex]

[tex]5=-6(x62-4x+4)-6(-4)[/tex]

[tex]5=-6(x-2)^2+24[/tex]                [tex][\becasue (a-b)^2=a^2-2ab+b^2][/tex]

Step 4: Subtract 24 from both sides.

[tex]5-24=-6(x-2)^2+24-24[/tex]

[tex]-19=-6(x-2)^2[/tex]

Step 5: Divide both sides by -6.

[tex]\frac{19}{6}=(x-2)^2[/tex]

Step 6: Taking square root on both sides.

[tex]\pm \sqrt{\frac{19}{6}}=(x-2)[/tex]

Step 7: Add 2 on both sides.

[tex]2\pm \sqrt{\frac{19}{6}}=x[/tex]

Therefore, the two solutions are [tex]x=2\pm \sqrt{\frac{19}{6}}[/tex].

The missing step for the given quadratic equation is:

  • "Add and subtract 4 in the parenthesis."

Given that the quadratic equation given, we can see that we are given:

[tex]0 = - 6x {}^{2} + 24x - 5[/tex]

Therefore, when we add the missing part which is to add and subtract 4 in the parenthesis, the the quadratic equation can be solved.

This would balance both sides and to find the value of x.

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