Respuesta :

itzBaraa

[tex]x=\frac{-b+-\sqrt{b^{2}-4ac}}{2a}[/tex]

a = 4, b = 3 and c = -10.

[tex]x=\frac{-(3)+-\sqrt{(3)^{2}-4(4)(-10)}}{2(4)} \\x=\frac{-3+-\sqrt{169}}{8} \\x=\frac{5}{4} , x=-2[/tex]

artasticdrawing

Answer:

A) x = -2, x = 1.25 I believe.

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