Suppose a fish population is currently 2800 and 3 years later the population is 25000. Use the explicit exponential model to find the rate of growth.


Express the rate of growth as a percentage. Round to the nearest tenth.

r=

Respuesta :

Answer: 107.5%

Step-by-step explanation:

The explicit exponential model for growth :

[tex]A=A_0(1+r)^t[/tex]    (1), where [tex]A_0[/tex] is the initial amount and r is the rate of interest and t is the time.

Given : Suppose a fish population is currently 2800 and 3 years later the population is 25000.

i.e. [tex]A_0=2800[/tex]

Put  [tex]A_0=2800[/tex], A = 25000 and t=3 in (1)

[tex]25000=2800(1+r)^3\\\\ (1+r)^3=\dfrac{25000}{2800}=8.92857142857\approx8.93[/tex]

Taking cube root on both sides , we get

[tex]1+r=(8.93)^{1/3}=2.07467697105\approx2.075\\\\ r=2.075-1=1.075=107.5\%[/tex]

Hence, the rate of growth = 107.5%

The rate of growth of the fish using the explicit exponential model in percentage is 107.5 %.

What is an exponent?

Exponential notation is the form of mathematical shorthand which allows us to write complicated expressions more succinctly. An exponent is a number or letter is called the base. It indicates that the base is to raise to a certain power. X is the base and n is the power.

Suppose a fish population is currently 2800 and 3 years later the population is 25000.

The explicit model is given as

[tex]\rm A = A_o (1+r)^t[/tex]

Where A₀ is the initial population of fish, t be the time and r be the rate.

We have

A₀ = 2800

A = 25000

t = 3

Then the equation will be

[tex]\rm 25000= 2800(1+r)^3[/tex]

On simplifying, we have

[tex]\begin{aligned} 8.9286 &= (1+r)^3\\\\1+r &= 2.07457\\\\r &= 1.07457 \approx 1.075 \\\\r &= 107.5 \% \end{aligned}[/tex]

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