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HONORS PHYSICS
GRAVITY AND CIRCULAR MOTION TEST
10-28-19
1. A dog sits 2.50 meters from the center of a merry go round and revolves at a tangential speed of
1.80 m/s. If the dog's mass is 21.0 kg, what is the magnitude of the centripetal force on the dog?

Respuesta :

Answer:

F = 27.22 N

Explanation:

Given that,

The length of the merry go round from center, R = 2.50 m

Tangential speed of the merry go round, v = 1.80 m/s

The mass of the dog, m = 21 Kg

The centripetal force is given by the formula,

                             F = mv² / R

Substituting the values in the above equation,

                             F = 21 Kg x (1.8 m/s)² / 2.50 m

                                = 27.22 N

Hence, the magnitude of the centripetal force on the dog, F = 27.22 N

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