Answer:
[tex]x=sin^-1(\frac{8.9}{10.9})[/tex]
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
In the right triangle LKJ of the figure
The sine of angle LKJ (x) is equal to divide the opposite side to angle LKJ (LJ) by the hypotenuse of the right triangle (KJ)
so
substitute the given values
[tex]sin(x)=\frac{8.9}{10.9}[/tex]
therefore
[tex]x=sin^-1(\frac{8.9}{10.9})[/tex]
