Answer:
210 N
Explanation:
The change in momentum of the ball is equal (in magnitude) to the impulse given to the pin, according to
[tex]\Delta p = F \Delta t[/tex] (1)
where
[tex]\Delta p[/tex] is the change in momentum of the ball
F is the force exerted on the pin
[tex]\Delta t[/tex] is the duration of the collision
For the bowling ball, we have
m = 7 kg (mass)
u = 6.0 m/s (initial velocity)
v = 4.5 m/s (final velocity)
So, the change in momentum (in magnitude) is
[tex]\Delta p = m(u-v)=(7)(6.0-4.5)=10.5 kg m/s[/tex]
We also know the duration of the collision,
[tex]\Delta t = 0.05 s[/tex]
And so if we re-arrange eq.(1), we find the force exerted on the pin:
[tex]F=\frac{\Delta p}{\Delta t}=\frac{10.5}{0.05}=210 N[/tex]
