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A small fish (m = 0.5 kg) moving at 2 m/s is followed by a bigger fish (m = 5 kg) moving at 3 m/s. (Show work)

a) What is the total momentum of this system before the big fish had its lunch?

b) What’s the momentum after lunch?

Respuesta :

MathPhys

Explanation:

a) Total momentum before:

p = (0.5 kg) (2 m/s) + (5 kg) (3 m/s)

p = 16 kg m/s

b) Total momentum after = momentum before

p = 16 kg m/s

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