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Terminal velocity is the fastest speed that an object can fall through the air. A skydiver reaches a terminal velocity of 120 miles per hour. What is the change in elevation of the skydiver after falling at terminal velocity for 15 seconds?

Respuesta :

thatandroidniba

Answer:

2640ft, or 1/2mi.

Step-by-step explanation:

120mi/hr*5280=633,600

633,600/3600 (to convert it from ft/hr to ft/sec) =176ft/sec

176x15=2640ft, which is equivalent to 1/2mi.

tatendagota

Answer:

146.7 m

Step-by-step explanation:

Data:

Let the terminal velocity, [tex]v_{t}[/tex] be  = 120 miles/h

                                                   =  53. 6448 m/s

The time taken for the fall, t      = 15 sec

Let, the initial velocity, u = 0

Therefore, the equation to calculate distance will be:

[tex]v^{2} = u^{2} + 2as[/tex]

where a = g = 9.81

           s = distance traveled

Therefore:

[tex](53.6448)^{2} = 0 + 2(9.81) s[/tex]

2877.76 = 19.62s

         s = 146.7 m

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