Answer:
u = 13.67 m/s
Explanation:
given,
window height = 2 m
window is 7.5 m off the ground on its path up
total distance from the ground to pass the window = 2 + 7.5 = 9.5 m
time taken to go past the window = 1.30 s
using equation of motion
[tex]S = u t +\dfrac{1}{2}gt^2[/tex]
[tex](2+7.5)= u\times 1.3 -0.5\times 9.8\times 1.3^2[/tex]
[tex]u\times 1.3 = 9.5 + 8.281[/tex]
u = 13.67 m/s
hence, the initial velocity of the ball is equal to 13.67 m/s
