Answer:
B) Its horizontal velocity component is the same as it was just as it was launched
Explanation:
From dynamic we know that free falling objects had two components of velocity
The only acceleration that takes place in this case is gravity in the y-component of velocity
[tex]v_{vx}=v_{ox}+at\\v_{y}=v_{oy}+gt[/tex]
Since a=0 and [tex]g=-9.8m/s^2=-32.2ft/s^2[/tex] that means that the velocity at the y-component changes with time but the horizontal component remain the same
[tex]v_{x}=v_{ox}[/tex]
This means that the horizontal velocity is not 0 but is the same as it was just as it was launched
