Answer:
The pressure of the gas is P=1.99 atm
Explanation:
Given:
Amount of gas substance, n=3.0 mol
Volume of the gaseus substance V=33.6 L
To find :
Pressure of the gas =?
Solution:
According to Ideal gas Law,
[tex]P V=n R T[/tex]
Where
p = pressure of the gas,
V = volume of the gas
n = amount of substance
R = ideal gas constant
T = temperature of the gas
Re-arranging the formula we get,
[tex]P V=n R T[/tex]
Substituting the values ,
[tex]P=\frac{3 \times 0.082 \mathrm{Latm} \mathrm{mol}^{-1} \mathrm{K}^{-1} \times 273.25 \mathrm{K}}{33.6 \mathrm{Lmol}^{-1}}[/tex]
[tex]P=\frac{3 \times 0.082 \mathrm{Latm} \mathrm{mol}^{-1} \mathrm{K}^{-1} \times 273.25 \mathrm{K}}{33.64 \mathrm{mol}^{-1}}[/tex]
[tex]P=\frac{3 \times 0.082 \mathrm{atm} \times 273.25}{33.6}[/tex]
[tex]P=\frac{67.19 a t m}{33.6}[/tex]
[tex]P=1.99 \mathrm{atm}[/tex]
Result :
The pressure of the gas is P=1.99 atm.
