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The longest passenger liner ever built was the France, 66,348 tons and 315.5 long. Suppose its front end passes the edge of a pier at a speed of 2.10 m/s while the ship is accelerating uniformly at 0.03 m/s^2. At what speed will the back end of the vessel pass the pier?

Respuesta :

Answer:

The back end of the vessel will pass the pier at 4.83 m/s

Explanation:

This is purely a kinetics question (assuming we're ignoring drag and other forces) so the weight of the boat doesn't matter. We're given:

Δd = 315.5 m

vi = 2.10 m/s

a = 0.03 m/s^2

vf = ?

The kinetics equation that incorporates all these variables is:

vf^2 = vi^2 + 2aΔd

vf = √(2.1^2 + 2(0.03)(315.5))

vf = 4.83 m/s

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