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if a ball is dropped from a height of 19.6m, what is the velocity with which the ball hits the ground?

Respuesta :

Answer:

V=√2hg

Distance/time=√2gh

19. 6/t=√2×9. 8×19. 6

19. 6/t=19. 6

t=1sec

MathPhys

Answer:

-19.6 m/s

Explanation:

Given:

y₀ = 19.6 m

y = 0 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: v

v² = v₀² + 2a (y − y₀)

v² = (0 m/s)² + 2(-9.8 m/s²) (0 m − 19.6 m)

v = ±19.6 m/s

Since the ball is falling downwards, v = -19.6 m/s.

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