Respuesta :
Answer:
a) 512.5 KW/m2
b) 40.75 KW/m2
c) 2 KW/m2
Explanation:
Given data;
T_2 = 325 K
T_1 = 275 K
dx = 0.20 mm
a) for aluminium K = 205 W/m k
heat flux [tex]= k \frac{dt}{dx}[/tex]
[tex]= 205 \frac{325 - 275}{0.02}[/tex]
= 512.5 KW/m2
b) for AISI 316 stainless steel
k = 16.3 W/ m k
heat flux [tex]= k \frac{dt}{dx}[/tex]
[tex]= 16.3 \frac{325 - 275}{0.02}[/tex]
= 40.75 KW/m2
C) for Concrete
k = 0.8 W/ m k
heat flux [tex]= k \frac{dt}{dx}[/tex]
[tex]= 0.8 \times \frac{325 - 275}{0.02}[/tex]
= 2 KW/m2
