Materials will have different energies associated with the electrons inside them. This is related to how strongly bound they are by their work function. If we sandwich a material with a very low energy between two materials with a high energy, we create a trap for an electron. If this trap is very narrow in one direction in comparison to the others, this is approximately a 1-dimensional box that confines the electron. What is the lowest energy of an electron in the box if the thinnest direction across the materials is 3.09 nm?

Question

contestada

Respuesta :

aristocles aristocles · Answer 1 · 2019-09-29T08:51:51+02:00

Answer:

E = 401.3 eV

Explanation:

As we know that the thinnest gap in the direction of metal is given as

[tex]t = 3.09 nm[/tex]

so here we can say that lowest energy of photon will not able to break this electron from above thickness

so we will have

[tex]E = \frac{hc}{\lambda}[/tex]

here we have

[tex]hc = 1240 nm-eV}[/tex]

also we have

[tex]\lambda = 3.09 nm[/tex]

so we will have

[tex]E = \frac{1240}{3.09} eV[/tex]

[tex]E = 401.3 eV[/tex]