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A pipe with a diameter of 2 cm is attached to a garden hose with a nozzle. If the velocity of how in the pipe is 2 m/s. what is the velocity of the flow at the nozzle when it is adjusted to have a diameter of 4 mm?

Respuesta :

Answer:

velocity at nozzle is given as

[tex]v_2 = 50 m/s[/tex]

Explanation:

As we know that volume flow rate through the pipe is always constant

so we can say that volume flow rate is given as

[tex]Q = \frac{dV}{dt}[/tex]

[tex]Q = area \times speed[/tex]

so we will have

[tex]A_1 v_1 = A_2v_2[/tex]

here we have

[tex]A_1 = \pi r_1^2[/tex]

[tex]A_2 = \pi r_2^2[/tex]

now we have

[tex]\pi (2^2) 2 m/s = \pi (0.4)^2 v_2[/tex]

[tex]v_2 = 50 m/s[/tex]

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