Answer:
[tex]r=\frac{1}{75}[/tex] Ω≈0.01333Ω
Explanation:
You can check the internal resistance model in the image I attached you.
Now using Kirchhoff's voltage law:
ε=[tex]Ir+IR[/tex] (1)
Where:
[tex]IR=V_R=LoadVoltage=10V[/tex]
ε=12V
[tex]I=150A[/tex]
Evaluating the data provide in (1)
[tex]r=\frac{12-10}{150} =\frac{1}{75}[/tex]≈0.01333Ω