Answer:[tex]0.0686 m^3[/tex]
Explanation:
Given
No of moles=2
[tex]T=25^{\circ}\approx 298 K[/tex]
[tex]P_1=210 KPa[/tex]
[tex]T_2=48 ^{\circ}\approx 321 k[/tex]
[tex]P_2=77.7 KPa[/tex]
PV=nRT
Substitute
[tex]77.7\times V_2=2\times 8.314\times 321[/tex]
[tex]V_2=0.0686 m^3[/tex]
