Answer:
c. 15 m
Explanation:
We apply Newton's second law in the x direction:
∑Fₓ = m*a
120*cos(60°) = 50*a
[tex]a = \frac{120*cos(60^o)}{50} = 1.2 \frac{m}{s^2}[/tex]
Block kinematics
The block moves with uniformly accelerated movement, so we apply the following formula to calculate the distance
[tex]d = V_o*t + \frac{1}{2}*a*t^2[/tex]
[tex]d = 0 + \frac{1}{2}*1.2*5^2[/tex]
d = 15m
