Answer:1.624 m
Explanation:
Given
height of 2nd floor =5 m
time recorded is 0.58 sec
Let h be the height of third floor above 2 nd floor
[tex]h=ut+\frac{at^2}{2}[/tex]
here u=0
t=time taken to cover height h
[tex]h=\frac{gt^2}{2}[/tex] ----------1
Now time taken to complete whole building length
[tex]h+5=\frac{g(t+0.58)^2}{2}[/tex] ----------2
Subtract 1 form 2
[tex]5=\frac{g(2t+0.58)(0.58)}{2}[/tex]
Taking gravity [tex]g=1 m/s^2[/tex]
1=(2t+0.58)(0.58)
t=0.57 s
Substitute the value of t in 1
h=1.624 m