Answer:
Football will be in air for 2.8139 sec
Explanation:
We have given maximum height h = 9.7 meters
Angle of projection [tex]\Theta =38^{\circ}[/tex]
We know that maximum height is given by [tex]h=\frac{u^2sin^2\Theta }{2g}[/tex]
So [tex]9.7=\frac{u^2sin^{2}38^{\circ} }{2\times 9.8}[/tex]
[tex]u^2=501.5842[/tex]
u = 22.396 m/sec
Time of flight is given by
[tex]T=\frac{2usin\Theta }{g}=\frac{2\times 22.396\times \times sin38^{\circ}}{9.8}=2.8139sec[/tex]
