Respuesta :
Answer: The mass of carbon dioxide produced is 15.8 grams
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)
Mass of barium carbonate = 71.0 grams
Molar mass of barium carbonate = 197.34 g/mol
Putting values in equation 1:, we get:
[tex]\text{Moles of }BaCO_3=\frac{71.0g}{197.34g/mol}=0.360mol[/tex]
The chemical equation for the decomposition of barium carbonate follows:
[tex]BaCO_3(s)\rightarrow BaO(s)+CO_2(g)[/tex]
By Stoichiometry of the reaction:
1 mole of barium carbonate produces 1 mole of carbon dioxide.
So, 0.360 moles of barium carbonate will produce = [tex]\frac{1}{1}\times 0.360=0.360mol[/tex] of carbon dioxide.
Now, calculating the mass of carbon dioxide by using equation 1, we get:
Moles of carbon dioxide = 0.360 mol
Molar mass of carbon dioxide = 44 g/mol
Putting values in equation 1, we get:
[tex]0.360mol=\frac{\text{Mass of carbon dioxide}}{44g/mol}\\\\\text{Mass of carbon dioxide}=(0.360mol\times 44g/mol)=15.8g[/tex]
Hence, the mass of carbon dioxide produced is 15.8 grams
