Answer:
y = 20.41 in
T= 168.1 lb
Explanation:
From diagram
Total force balance in vertical direction
T= 89.1 + 79 lb
T= 168.1 lb
Now taking moment about point m
Mm= 0 Because system is in equilibrium position
79 x 43.45 = T x y
Now by putting the value of T
79 x 43.45 = 168.1 x y
y = 20.41 in
So the cable attached at distance of 20.41 in from the mid point of bar.
Tension in the cable = 168.1 lb
