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A skier is accelerating down a 30.0 degree hill at 3.80 m/s2. How long (in seconds) will it take her to reach the bottom of the hill, assuming she starts from rest and accelerates uniformly, if the elevation change is 130 m?

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lcmendozaf

Answer:

t = 11.69s

Explanation:

The distance traveled by the skier is given by:

[tex]D = \frac{H}{sin (30)}[/tex]   where H=130m

D = 260m

Now, the movement down the hill is described by:

[tex]D = Vo*t + \frac{a*t^2}{2}[/tex]  Solving for t:

[tex]t = \sqrt{\frac{2D}{a} } = 11.69s[/tex]

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