Answer:21.45 m/s
Explanation:
Given
Mass of sport car=920 kg
Mass of SUV=2300 kg
distance to which both car skid is 2.4 m
coefficient of friction ([tex]\mu [/tex])=0.8
Let u be the initial velocity of both car at the starting of skidding
and they finally come to zero velocity
[tex]v^2-u^2=2as[/tex]
[tex]acceleration=\mu g=0.8\times 9.8=7.84 m/s^2[/tex]
s=2.4 m
[tex]0-(u)^2=2\times (-7.84)\times 2.4[/tex]
u=6.13 m/s
so before colliding sport car must be travelling at a speed of
[tex]920\times v=(920+2300)\times 6.13[/tex] (conserving momentum)
v=21.45 m/s
