Answer:
[tex]a=(6.8)\ m/s^2[/tex]
Explanation:
Given that,
An object starts from rest at the origin (x₀ = 0) and travels in a straight line with a constant acceleration (a = constant).
The relation between the position (x) and time (t) is given by :
[tex]x=(3.4t^2)\ m/s^2[/tex]
Let v is the velocity of the object.
[tex]v=\dfrac{dx}{dt}[/tex]
[tex]v=\dfrac{d(3.4t^2)}{dt}[/tex]
[tex]v=(6.8t)\ m/s[/tex]
Let a is the acceleration of the object. It is given by :
[tex]a=\dfrac{dv}{dt}[/tex]
[tex]a=\dfrac{d(6.8t)}{dt}[/tex]
[tex]a=(6.8)\ m/s^2[/tex]
So, the acceleration of the object is [tex](6.8)\ m/s^2[/tex]. Hence, this is the required solution.
