Respuesta :
Answer : The molar heat of solution of KBr is 19.9 kJ/mol
Explanation :
Mass of KBr = 7.00 g
Molar mass of KBr = 119 g/mole
Heat capacity = 2.72 kJ/K
Change in temperature = 0.430 K
First we have to calculate the moles of KBr.
[tex]\text{ Moles of }KBr=\frac{\text{ Mass of }KBr}{\text{ Molar mass of }KBr}=\frac{7.00g}{119g/mole}=0.0588moles[/tex]
Now we have to calculate the heat of the reaction.
[tex]q=c\times \Delta T[/tex]
where,
q = amount of heat = ?
[tex]c[/tex] = heat capacity = [tex]2.72kJ/K[/tex]
[tex]\Delta T[/tex] = change in temperature = 0.430 K
Now put all the given values in the above formula, we get:
[tex]q=2.72kJ/K\times 0.430K[/tex]
[tex]q=1.17kJ[/tex]
Now we have to calculate the molar heat of solution of KBr.
[tex]\text{Molar heat of solution of }KBr=\frac{q}{n}[/tex]
where,
n = number of moles of KBr
[tex]\text{Molar heat of solution of }KBr=\frac{1.17kJ}{0.0588moles}=19.9kJ/mol[/tex]
Therefore, the molar heat of solution of KBr is 19.9 kJ/mol
