contestada

A type of transmission line for electromagnetic waves consists of two parallel conducting plates (assumed infinite in width) separated by a distance a. Each plate carries the same uniform surface current density of 16.0 A/m, but the currents run in opposite directions. What is the magnitude of the magnetic field between the plates at a point 1.00 mm from one of the plates if a = 0.800 cm? (μ0 = 4π × 10-7 T · m/A)

Respuesta :

Answer:

[tex]B=2.01 \times 10^{-5}\ T[/tex]

Explanation:

Distance between plates = 0.8 cm

Distance from one plate = 1 mm

Current density (J)= 16 A/m

Currents are flowing in opposite direction.

[tex]\mu _o=4\pi \times 10^{-7}[/tex]

When current is flowing in opposite direction then magnetic field given as

[tex]B=\dfrac{\mu _oJ}{2}+\dfrac{\mu _oJ}{2}[/tex]

[tex]B=\mu _oJ[/tex]

Now by putting the values we get

[tex]B=4\pi \times 10^{-7}\times 16[/tex]

[tex]B=2.01 \times 10^{-5}\ T[/tex]

onyebuchinnaji

The magnitude of the magnetic field between the plates at the given point is 2.011 x 10⁻⁵ T.

What is magnetic field?

The magnitude of magnetic field between the plates due to the current flowing in opposite directions is determined by using the following formula;

B = μ₀J/2 + μ₀J/2

B = μ₀J

where;

  • μ₀ is permeability of free space = 4π x 10⁻⁷ T.m/A
  • J is current density

Substitute the given parameters and solve for the magnetic field as follows;

B = (4π x 10⁻⁷) x (16)

B = 2.011 x 10⁻⁵ T

Thus, the magnitude of the magnetic field between the plates at the given point is 2.011 x 10⁻⁵ T.

Learn more about magnetic field here: https://brainly.com/question/7802337

Otras preguntas