Tracking a Satellite The path of a satellite orbiting the earth causes it to pass directly over two tracking stations A and B, which are 50 mi apart. When the satellite is on one side of the two stations, the angles of elevation at A and B are mea- sured to be 87.0???? and 84.2????, respectively.
(a) How far is the satellite from station A?
(b) How high is the satellite above the ground?

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Answer:

A)the satellite is at a distance of 1018.4 miles

B) the height of the satellite above the ground is 1017 miles.

Step-by-step explanation:

The diagram below shows the situation graphically so it's easier to understand.

To calculate this we need to use the tangent definition I.E. [tex]tan(\alpha ) = \frac{oposite side}{adyacent side}[/tex]

so for angle at point A it would be

tan(87) = h /x

for angle at pint B it would be tan

(84.2) = h / (x+50)

since h is the same for both we can pass terms and replace, then solve for x

tan(87)*x = h

tan (84.2)*(x+50) = h

tan(87) * x = tan (84.2) * (x+50)

[tex]\frac{tan (87)}{tan (84.2)}[/tex] = [tex]\frac{x+50}{x}[/tex]

1.938 = 1 + [tex]\frac{50}{x}[/tex]

1.938 -1 = [tex]\frac{50}{x}[/tex]

x = [tex]\frac{50}{0.938}[/tex] = 53.3 mi

then using the tangent formula from before we can calculate h

tan(87) = h / 53.3

tan (87) / 53.3 = h

h = 1017 mi

then we can use the cos formula to calculate d

cos 87 = x / d

d =  53.3 / cos 87 = 1018.4 mi

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Using the Sine rule and Trigonometry, the distance of the satellite from Station A and its height above the ground is 325.15 miles and 324.7 miles

Using the Sine rule :

C = 180 - (84.2 + 87) = 8.8°

c/SinC = b/SinB

The distance of satellite from Station A is :

50/sin(8.8) = b/sin(84.2)

b = [sin(84.2) × 50] ÷ sin(8.8)

b = (49.74) ÷ 0.153

b = 325.15 miles

The height of the satellite above the ground :

Using trigonometry : SOHCAHTOA

Sin(87°) = opposite / hypotenus

Sin(87°) = d/325.15

d = sin(87°) × 325.15

d = 324.7 miles

Hence, the height of the satellite is 324.7 miles.

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