Answer:3.67 m/s
Explanation:
mass of block(m)=2 kg
Velocity of block=6 m/s
spring constant(k)=2 KN/m
Spring compression x=15 cm
Conserving Energy
energy lost by block =Gain in potential energy in spring
[tex]\frac{m(v_1^2-v_2^2)}{2}=\frac{kx^2}{2}[/tex]
[tex]2\left [ 6^2-v_2^2\right ]=2\times 10^3\times \left [ 0.15\right ]^2[/tex]
[tex]v_2=3.67 m/s[/tex]
