Answer:
yes, Tony’s statement correct
Step-by-step explanation:
Lets solve both Left hand side and right hand side separately and then equate.
LHS
[tex]7\frac{1}{4} -3\frac{3}{4} = \frac{29}{4} -\frac{15}{4}[/tex]
= [tex]\frac{29}{4} -\frac{15}{4 } = \frac{14}{4}[/tex]
Taking RHS
[tex]4\frac{1}{4} -\frac{3}{4} = \frac{17}{4} -\frac{3}{4} =\frac{14}{4}[/tex]
clearly LHS = RHS hence both quantities are equal to each other
