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A tennis ball is dropped from 1.62 m above the
ground. It rebounds to a height of 0.963 m.
With what velocity does it hit the ground?
The acceleration of gravity is 9.8 m/s. (Let
down be negative.)
Answer in units of m/s.
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Respuesta :

MathPhys

Answer:

-5.63 m/s

Explanation:

Given:

y₀ = 1.62 m

y = 0 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: v

v² = v₀² + 2a (y − y₀)

v² = (0 m/s)² + 2(-9.8 m/s²) (0 m − 1.62 m)

v = -5.63 m/s

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