Answer: [tex]\bold{\dfrac{1}{9}}[/tex]
Step-by-step explanation:
There is 1 possibility of getting a sum of 2 → (1 + 1)
There are 2 possibilities of rolling a 3 → (1 + 2 and 2 + 1)
There is 1 possibility of rolling a 12 → ( 6 + 6)
There are 36 total number of possible outcomes.
Consider that success for this problem is rolling a 2, 3, or 12:
[tex]\dfrac{\text{number of successes}}{\text{total number of possible outcomes}}=\dfrac{1+2+1}{36}\quad =\dfrac{4}{36}\quad \implies \large\boxed{\dfrac{1}{9}}[/tex]
