Answer:
Wavelength of incident light, [tex]\lambda = 612 nm[/tex]
Given:
Distance between slit and screen, x = 5.00 m
slit width, d = 0.180 mm
width of the fringe, [tex]\beta = 1.70 cm = 0.017 m[/tex]
Solution:
To calculate the wavelength of the incident light, [tex]\lambda [/tex]:
[tex]\beta = \frac{x\lambda }{d}[/tex]
[tex]\lambda = \frac{\beta d}{x}[/tex]
[tex]\lambda = \frac{0.017\times 0.180\times 10^{- 3}}{5} = 6.12\times 10^{- 7}m = 612 nm[/tex]
[tex]\lambda = 612 nm[/tex]
