Answer:
19.2 mA
Explanation:
C = 9 micro farad = 9 x 10^-6 F
L = 16 H
f = 60 Hz
Vrms = 116 V
[tex]X_{L}=2\times \pi \times f\times L[/tex]
[tex]X_{L}=2\times 3.14 \times 60 \times 16[/tex]
XL = 6028.8 ohm
[tex]X_{C}=\frac{1}{2 \times \pi \times f \times C}[/tex]
[tex]X_{C}=\frac{1}{2\times 3.14 \times 60 \times 9 \times 10^{-6}}[/tex]
Xc = 294.88 ohm
Let Z be the impedance of the circuit.
[tex]Z=\sqrt{X_{L}^{2}+X_{C}^{2}}[/tex]
[tex]Z=\sqrt{6028.8^{2}+294.88^{2}}[/tex]
Z = 6036 ohm
[tex]I_{rms}=\frac{V_{rms}}{Z}[/tex]
[tex]I_{rms}=\frac{116}{6036}[/tex]
Irms = 0.0192 A
Irms = 19.2 mA
