Answer:
The decrease in volume of the cylinder, V = [tex]129.88 cm^{3}[/tex]
Given:
Diameter of the circular cross section, d = 7.20 ± 0.009
Distance moved by the piston, h = 3.190 ± 0.001
Solution:
Since the values are given with some percentage error in the format x±[tex]\Delta x[/tex], so calculate the decrease in volume we consider the 'x' part of the values.
Now, the decrease in volume of cylinder is given by:
V = [tex]\pi r^{2}h = \pi (\frac{d}{2})^{2}h[/tex]
Therefore,
V = [tex]\pi\times (\frac{7.20}{2})^{2}\times 3.190 = 129.88 cm^{3}[/tex]
