Answer:
The velocity is 31.25 m/s and direction is toward west.
Explanation:
Given that,
Distance [tex]h= 1790 km = 1.790\times10^{6}\ m[/tex]
Magnetic field [tex]B=4\times10^{-8}\ T[/tex]
Mass of proton [tex]m=1.673\times10^{-21}\ Kg[/tex]
Radius of earth [tex]R =6.38\times10^{6}\ m[/tex]
Radius of orbit [tex]r=R+h[/tex]
[tex]r=6.38\times10^{6}+1.790\times10^{6}[/tex]
[tex]r=8170000\ m[/tex]
We need to calculate the speed
Using formula of magnetic field
[tex]Bvq=\dfrac{mv^2}{r}[/tex]
[tex]v=\dfrac{Bqr}{m}[/tex]
Put the value into the formula
[tex]v=\dfrac{4\times10^{-8}\times1.6\times10^{-19}\times8170000}{1.673\times10^{-21}}[/tex]
[tex]v=31.25\ m/s[/tex]
Hence, The velocity is 31.25 m/s and direction is toward west.
