Answer:
[tex]\rho = 1848.03 kg m^{-3}[/tex]
Explanation:
given data:
density of water \rho = 1 gm/cm^3 = 1000 kg/m^3
height of water = 20 cm =0.2 m
Pressure p = 1.01300*10^5 Pa
pressure at bottom
[tex]P = P_{fluid} + P_{h_2 o}[/tex]
[tex]P = P_{fluid} + \rho g h[/tex]
[tex] P_{fluid} = P - \rho g h[/tex]
= 1.01300*10^5 - 1000*0.2*9.8
= 99340 Pa
[tex]p_{fluid} = P_{atm} + \rho g h_{fluid}[/tex] h_[fluid} = 0.307m
[tex]99340 = 104900 + \rho *9.8*0.307[/tex]
[tex]\rho = 1848.03 kg m^{-3}[/tex]