Answer : The total pressure at equilibrium is 0.350 atm
Solution : Given,
Initial pressure of [tex]HI[/tex] = 0.350 bar
[tex]K_p[/tex] = 0.016
The given equilibrium reaction is,
[tex]2HI(g)\rightleftharpoons H_2(g)+I_2(g)[/tex]
Initially 0.350 0 0
At equilibrium (0.350-2x) x x
The total pressure at equilibrium = [tex](0.350-2x)+x+x=0.350-2x+2x=0.350atm[/tex]
Thus, the total pressure at equilibrium is 0.350 atm
The total pressure of the system at equilibrium is mathematically given as
Tp=0.350atm
Question Parameters:
Kp for the reaction is 0.016.
If 0.350 atm of HI(g) is sealed in a flask
Generally the equation for the Reaction is is mathematically given as
2 HI(g) H2(g) + I2(g)
Giving (0.350-2x) ---At equilibrium
Therefore, the total pressure at equilibrium is
Tp= (0.350-2x)+x+x
Tp=0.350-2x+2x
Tp=0.350atm
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