In young’s double slit experiment, the measured fringe width is 0.5 mm for a Sodium light of 589 nm at a distance of 1.5 m. A bright fringe is at a distance of 1 cm from the center.

A) Find the order of the bright fringe
B) Calculate the width of the bright fringe

Respuesta :

Answer:

(A).  The order of the bright fringe is 6.

(B). The width of the bright fringe is 3.33 μm.

Explanation:

Given that,

Fringe width d = 0.5 mm

Wavelength = 589 nm

Distance of screen and slit D = 1.5 m

Distance of bright fringe y = 1 cm

(A) We need to calculate the order of the bright fringe

Using formula of wavelength

[tex]\lambda=\dfrac{dy}{mD}[/tex]

[tex]m=\dfrac{d y}{\lambda D}[/tex]

Put the value into the formula

[tex]m=\dfrac{1\times10^{-2}\times0.5\times10^{-3}}{589\times10^{-9}\times1.5}[/tex]

[tex]m=5.65 = 6[/tex]

(B). We need to calculate the width of the bright fringe

Using formula of width of fringe

[tex]\beta=\dfrac{yd}{D}[/tex]

Put the value in to the formula

[tex]\beta=\dfrac{1\times10^{-2}\times0.5\times10^{-3}}{1.5}[/tex]

[tex]\beta=3.33\times10^{-6}\ m[/tex]

[tex]\beta=3.33\ \mu m[/tex]

Hence, (A).  The order of the bright fringe is 6.

(B). The width of the bright fringe is 3.33 μm.