Answer:
[tex]E=1.56\times 10^{-2} kcal[/tex]
Explanation:
To maintain the body temperature we have to take energy equal to how much energy we loose.
And we know that,
[tex]1kcal=4184J\\1J=\frac{1}{4184}kcal\\1J=2.4\times 10^{-4}kcal[/tex]
Now the energy loss is -65.3 J and this amount of energy we have to take.
[tex]E=65.3\times 2.4\times 10^{-4} kcal\\E=1.56\times 10^{-2} kcal[/tex]
Therefore, amount of food taken in one day to maintain body temperature is [tex]E=1.56\times 10^{-2} kcal[/tex]
