Suppose that a car traveling with constant speed to the west takes a 90° left turn toward south. Which of the following statements about its acceleration in the midpoint of the turn is correct? Flag question Select one: a. The acceleration is toward the north-west. b. The acceleration is toward south. c. The acceleration is toward the south-east. O d. Since the speed s constant the acceleration is zero

[tex]\overrightarrow{a}=\frac{\overrightarrow{v_{f}}-\overrightarrow{v_{i}}}{t_{f}-t_{i}}\\\\\therefore \overrightarrow{a}=\frac{-v\widehat{j}+v\widehat{i}}{t_{f}-t_{i}}\\\\\overrightarrow{a}=\frac{1}{\Delta t}(v\widehat{i}-v\widehat{j})[/tex]

From the direction of the acceleration vector we conclude that the direction is towards south east.

Vespertilio Vespertilio · Answer 2 · 2019-09-06T14:23:43+02:00

Answer:

option (c)

Explanation:

Let the speed of car is v.

It is travelling along the west direction. So write the initial velocity of the car in vector form.

[tex]\overrightarrow{v_{1}}=-v\widehat{i}[/tex]

Now it takes a left turn at 90°, write the final velocity in vector form.

[tex]\overrightarrow{v_{2}}=-v\widehat{j}[/tex]

Acceleration is given by the rate of change of velocity, so the direction of acceleration is same as the direction of change in velocity.

[tex]\overrightarrow{a}=\frac{\overrightarrow{v_{2}}-\overrightarrow{v_{1}}}{t}[/tex]

[tex]\overrightarrow{a}=\frac{-v\widehat{j}+v\widehat{i}}{t}=\frac{v\widehat{i}-v\widehat{j}}{t}[/tex]

The direction of the acceleration is towards south east.