Answer:
Step-by-step explanation:
Let X be the mean score for physics test, and Y be the mean score for Chemistry test
Given that X is normal N(46,4)
Y is N(77,9)
when y>52 and x >90 to compare we have to convert these into corresponding Z scores
[tex]x>52[/tex]⇒[tex]z>\frac{52-46}{4} \\z>1.5[/tex]
For [tex]y>90, \\Z>\frac{90-77}{9} =1.444[/tex]
Since Z>1.444 has more area than z>1.5 we find that it is more likely that
a student gets over 90 on the Chemistry test