Answer:
The pressure drop over the length of the pipe is 140000 kPa.
Explanation:
let R be the radius of the pipe.
let V be the volume flow rate.
let v be the average speed of the Glycerin.
let A be the area of the pipe.
then, the volume flow rate is given by:
V = v×A
V = [π×P×r^4]/[8×Vi×L]
[π×P×r^4]/[8×Vi×L] = v×A
P = [8×Vi×L]×v×A/[π×r^4]
= [8×Vi×L×v×π×r^2]/[π×r^4]
= [8×Vi×L×v]/[r^2]
= [8×1.5×(25×10^-2)×(1.2)]/[(5×10^-2)^2]
= 140000 kPa
Therefore, the pressure drop over the length of the pipe is 140000 kPa.
