A flask that can withstand an internal pressure of 2500 torr, but no more, is filled with a gas at 21.0C and 758 torr and heated. At what temperature will it burst?

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

[tex]P\propto T[/tex]

or,

[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]

where,

[tex]P_1[/tex] = initial pressure of gas = 758 torr

[tex]P_2[/tex] = final pressure of gas = 2500 torr

[tex]T_1[/tex] = initial temperature of gas = [tex]21.0^oC=273+21.0=294K[/tex]

[tex]T_2[/tex] = final temperature of gas = ?

Now put all the given values in the above equation, we get:

[tex]\frac{758torr}{294K}=\frac{2500torr}{T_2}[/tex]

[tex]T_2=969.66K[/tex]

Thus, the temperature will be 969.66 K