Answer:
7 x 10^5 V/s
Explanation:
capacitance, C = 2 micro farad = 2 x 10^-6 F
displacement current, id = 1.4 A
Let dV/dt be the rate of change of potential difference between the plates of the capacitor.
The relation between the displacement current and the rate of change of potential difference is given by
[tex]i_{d}=C\frac{dV}{dt}[/tex]
[tex]1.4=2\times10^{-6}\times\frac{dV}{dt}[/tex]
dV/dt = 7 x 10^5 V/s
Thus, the rate of change of potential difference between the plates is given by 7 x 10^5 V/s.
