Answer:
1. 7 = a
2. 20 = n
3. 324 = w
4. ⅞ = k
5. 3 = p
6. 3 = t
7. 15,2 = m
8. 15,6 = k
9. 14⅔ = b
10. 1 = n
Step-by-step explanation:
10.
10.
[tex] \frac{6(7 - 2)} {3(8) + 6} = \frac{6(5)}{24 + 6} = \frac{30}{30} = 1[/tex]
9.
[tex] \frac{2(40 + 4)}{3(3 - 1)} = \frac{2(44)}{3(2)} = \frac{88}{6} = 14 \frac{4}{6} = 14 \frac{2}{3} [/tex]
8. ₁
5,7
+ 9,8
_____
15,5 = k
7.
18,4
- 3,2
_____
15,2 = m
6.
[tex] \frac{15 - 6}{27 - 24} = \frac{9}{3} = 3[/tex]
5.
[tex] \frac{18 - 3}{2 + 3} = \frac{15}{5} = 3[/tex]
4. Find the Least Common Denominator [LCD], which in this case is 8:
¼ → 2⁄8
2⁄8 + ⅝ = ⅞; ⅞ = k
3.
[tex]3^2 = 9 \\ 6^2 = 36[/tex]
9 × 36 = 324; 324 = w
2.
[tex] -4^2 = - 16[/tex]
36 - 16 = 20; 20 = n
1.
[tex]2^3 = 8[/tex]
8 - 1 = 7; 7 = a
As you can see, there is somehow an extra 10 in my work, and I do not know how to get rid of it after trying all sorts of ways, so just refrain from it.
I am joyous to assist you anytime.
