Answer:
.65 s
Explanation:
Torque will create angular acceleration in the door .
Torque = force x perpendicular distance from the hinge
= 220 x 1.2 = 264 Nm
Moment of inertia of the door about hinge
I = 1 /3 x m l²
m is mass of the door and l is its width
= [tex]\frac{730\times1.2\times1.2}{3\times9.8}[/tex]
= 35.755 kg m²
Angular acceleration α = Torque / moment of inertia
= [tex]\frac{264}{35.755}[/tex]
= 7.38 rad s²
Angle to be rotated θ = π/2
π/2 = .5 α t²
1.56 = .5 x 7.38 t²
t = 0.65 s