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You can enter compound units that are combinations of other units that are multiplied together. to enter the ⋅ explicitly, type (shift + 8) on the keyboard, or use the template in the templates symbol menu menu. torque can be calculated by multiplying the force (n) applied at 90∘ to the lever arm at a distance (m) from the pivot point (point of rotation), the compound si unit for the torque is n⋅m. if the force (at 90∘ to the lever arm) applied is 15 n and it is applied at 2.0 m from the pivot point (point of rotation), what is the torque on the lever?

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skyluke89

Answer:

[tex]30 N \cdot m[/tex]

Explanation:

The torque applied by a force can be calculated as

[tex]\tau = F d sin \theta[/tex]

where

F is the magnitude of the force

d is the length of the arm

[tex]\theta[/tex] is the angle between the direction of the force and the arm

In this problem, we have

F = 15 N

d = 2.0 m

[tex]\theta=90^{\circ}[/tex]

Substituting into the equation, we find

[tex]\tau = (15)(2.0) sin 90^{\circ}=30 N \cdot m[/tex]

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