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A movie theater sells tickets at different prices. Adults are charged $8.50 per ticket, and children are charged $5.50 per ticket. If the theater sells 26 tickets for $194, how many adult tickets and how many child tickets were sold?

Respuesta :

Answer:

9 child tickets and 17 adult tickets were sold.

Step-by-step explanation:

Let the number of adult tickets sold be [tex]a[/tex]

and the number of child tickets be [tex]c[/tex].

The theater sold a total number of 26 tickets.

This means that: [tex]a+c=26[/tex].....eqn1

The theater made a total sale od $194.

This implies that:

[tex]8.5a+5.5c=194[/tex]...eqn2

We make [tex]a[/tex] the subject in equation 1: [tex]a=26-c[/tex]...eqn3

Substitute equation (3) into equation (2)

[tex]8.5(26-c)+5.5c=194[/tex]

Expand to get: [tex]221-8.5c+5.5c=194[/tex]

[tex]-8.5c+5.5c=194-221[/tex]

[tex]-8.5c+5.5c=194-221[/tex]

[tex]-3c=-27[/tex]

[tex]\implies c=9[/tex]

Put c=9 into equation (3) to get:[tex]a=26-9=17[/tex]

Therefore 9 child tickets and 17 adult tickets were sold.